(UEFS-BA) Se log (a - b) c = 5 e log (a + b) c = 4, então o valor de logc (a² - b²) é:
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5
(UEFS-BA) Se 
e 
, então o valor de 
é:
![log_c\ (a-b)=5\ , \ log_c \ (a+b)=4\ e \ log_c \ (a^2-b^2)={?} \\
\\
\\
\\ \ \ \ log_c \ (a^2-b^2)=log_c \ [(a+b)\cdot(a-b)]\\
\\=log_c \ (a+b)+log_c \ (a-b)\\
\\=4+5\\
\\=9](https://tex.z-dn.net/?f=log_c%5C+%28a-b%29%3D5%5C+%2C+%5C+log_c+%5C+%28a%2Bb%29%3D4%5C+e+%5C+log_c+%5C+%28a%5E2-b%5E2%29%3D%7B%3F%7D+%5C%5C%0A%5C%5C%0A%5C%5C%0A%5C%5C+%5C+%5C+%5C+log_c+%5C+%28a%5E2-b%5E2%29%3Dlog_c+%5C+%5B%28a%2Bb%29%5Ccdot%28a-b%29%5D%5C%5C%0A%5C%5C%3Dlog_c+%5C+%28a%2Bb%29%2Blog_c+%5C+%28a-b%29%5C%5C%0A%5C%5C%3D4%2B5%5C%5C%0A%5C%5C%3D9 "log_c\ (a-b)=5\ , \ log_c \ (a+b)=4\ e \ log_c \ (a^2-b^2)={?} \\
\\
\\
\\ \ \ \ log_c \ (a^2-b^2)=log_c \ [(a+b)\cdot(a-b)]\\
\\=log_c \ (a+b)+log_c \ (a-b)\\
\\=4+5\\
\\=9")
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