Question

TRANSFORME PARA KELVIN ( Cálculo)
a) 150 °C ( CELSIOS)

b)30°F (FAHRENHEIT

Answer 1

a) 150°C 

C/5 = K-273/5
150/5 = K-273/5
150 = K - 273
K = 150 + 273
K = 423

b) 30°F

30/9 = K-273/5
Multiplicando cruzado teremos:
9K - 2457 = 150
9K = 2457 + 150
9K = 2607
K = 2607/9
K = 289,67

Answer 2

a)
F=9/5.C+32
F=9/5.150+32
F=9.150/5+32
F=1350/5+32
F=270+32
F=302
b)
C=5/9.(F-32)
C=5/9.(30-32)
C=5.(-2)/9
C=-10/9
C=-1,11