Question

TRANSFORME PARA FAHRENHEIT

a) 10 K
b) 90°C

Answer 1

a) K = 10
     K = c+273
     10 = c + 273
     - c = 273-10 *(-1)
c = -273+10
c= -263

c/5=f-32/9
-263/5=f-32/9
-52,6=f-32/9

f-32=-473,4
f=473,4+32
f= 441.4 ºF

b) c/5=f-32/9
90/5=f-32/9
18=f-32/9
f-32=162
f=162+32
f=194ºF