Question

Transforme em uma única potencia cada produto a seguir
a) 10⁵.10 =

b) 3⁷.3⁴.3 =

c) a⁴.a⁷.a² =

d) (1/2)⁵.(1/2)³ =

e) (3/5)².(3/5)⁷.(3/5) =

f) (0,9)².(0,9)⁶.(0,9)⁵ =

g) 2⁶.2³ =

h) n.n⁸.n¹² =

i) (2/3)³.(2/3)³ =

j) (1,1)¹⁰.(1,1).(1,1)⁶.(1,1)³ =​​

Answer 1

Resposta:

a) 10⁵.10 = $10^{5 + 1} =$ $10^{6}$

b) 3⁷.3⁴.3 = $3^{7 + 4 + 1} = 3^{12}$

c) a⁴.a⁷.a² = $a^{4 + 7 + 2} = a^{13}$

d) (1/2)⁵.(1/2)³ = $(\frac{1^{5} }{2}) . (\frac{1^{2} }{2}) = (\frac{1}{2})^{5 + 2} = (\frac{1}{2})^{7}$

e) (3/5)².(3/5)⁷.(3/5) = $(\frac{3}{5})^{2} . (\frac{3}{5})^{7} . (\frac{3}{5}) = (\frac{3}{5})^{2 + 7 + 1} = (\frac{1}{5})^{10}$

f) (0,9)².(0,9)⁶.(0,9)⁵ = $(0,9)^{2} . (0,9)^{6} . (0,9)^{5} = (0,9)^{2 + 6 + 5} = (0,9)^{13}$

g) 2⁶.2³ = $2^{6} . 2^{2} = 2^{6+2} = 2^{8\\}$

h) n.n⁸.n¹² = $n . n^{2} . n^{12} = n^{12 + 2 + 1} = n^{15}$

i) (2/3)³.(2/3)³ = $(\frac{2}{3}) ^{2} . (\frac{2}{3}) ^{2} = (\frac{2}{3}) ^{2 + 2} = (\frac{2}{3}) ^{4}$

j) (1,1)¹⁰.(1,1).(1,1)⁶.(1,1)³ =​​  $(1,1)^{10} . (1,1) . (1,1)^{6} . (1,1)^{2} = (1,1)^{10 + 1 + 6 + 2} = (1,1)^{19}$

Bons Estudos!!