Question

Transforme as potenciações em multiplicações e resolva-as:
a) (1/2)²

b) (1/2)³

c) (2/5)²

d) (7/8)²

e) (1/10)²

f) (6/5)³

g) (10/11)²

h) (8/17)²​

Answer 1

Explicação passo-a-passo:

a) (1/2)²

½ x ½=¼

b) (1/2)³

½ x ½ x ½=⅛

c) (2/5)²

²/5 x²/5= 4/25

d) (7/8)²

⅞ x ⅞=49/64

e) (1/10)²

¹/10 x ¹/10=1/100

f) (6/5)³

6/5 x 6/5 x 6/5= 216/125

g) (10/11)²

10/11 x 10/11=100/121

h) (8/17)²

8/17 x 8/17=64/289

Answer 2

Resposta:

$\text{Leia abaixo}$

Explicação passo-a-passo:

$a)\: (\dfrac{1}{2})^2 = \dfrac{1^2}{2^2} = \dfrac{1}{4}$

$b)\: (\dfrac{1}{2})^3 = \dfrac{1^3}{2^3} = \dfrac{1}{8}$

$c)\: (\dfrac{2}{5})^2 = \dfrac{2^2}{5^2} = \dfrac{4}{25}$

$d)\: (\dfrac{7}{8})^2 = \dfrac{7^2}{8^2} = \dfrac{49}{64}$

$e)\: (\dfrac{1}{10})^2 = \dfrac{1^2}{10^2} = \dfrac{1}{100}$

$f)\: (\dfrac{6}{5})^3 = \dfrac{6^3}{5^3} = \dfrac{216}{125}$

$g)\: (\dfrac{10}{11})^2 = \dfrac{10^2}{11^2} = \dfrac{100}{121}$

$h)\: (\dfrac{8}{17})^2 = \dfrac{8^2}{17^2} = \dfrac{64}{289}$