Transforme as medidas em radianos.
Anexos:
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Soluções para a tarefa
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Olá
Para transformar, basta aplicar uma regra de simples. Para isso, usaremos a uma base (medida) conhecida.
Sabemos que π equivale a 180º no ciclo trigonométrico. Essa será nossa base.
Sempre pensaremos dessa maneira:
Se π vale 180, então a medida dada pela questão vale X.
Vamos escrever isso, resolvendo o item A)
A)

Agora, basta multiplicar em cruz.
Não se preocupe com o π, ele irá se cancelar no final da conta.

Isola o x, passando o π para o outro lado dividindo.

Como o procedimento é o mesmo, irei fazer as contas direto para os próximos itens.
B)

C)

D)

E)

Dúvidas? Deixe nos comentários.
Dica: Quer aprender de verdade? Veja o passo a passo do item A) e em seguida tente fazer os outros sozinho.
Para transformar, basta aplicar uma regra de simples. Para isso, usaremos a uma base (medida) conhecida.
Sabemos que π equivale a 180º no ciclo trigonométrico. Essa será nossa base.
Sempre pensaremos dessa maneira:
Se π vale 180, então a medida dada pela questão vale X.
Vamos escrever isso, resolvendo o item A)
A)
Agora, basta multiplicar em cruz.
Não se preocupe com o π, ele irá se cancelar no final da conta.
Isola o x, passando o π para o outro lado dividindo.
Como o procedimento é o mesmo, irei fazer as contas direto para os próximos itens.
B)
C)
D)
E)
Dúvidas? Deixe nos comentários.
Dica: Quer aprender de verdade? Veja o passo a passo do item A) e em seguida tente fazer os outros sozinho.
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