Transformar 4×39 F em graus Celsius
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Transformar 4×39 F em graus Celsius
![\dfrac{TC}{5} =\dfrac{TF - 32}{9} \\\\\\ \dfrac{TC}{5} =\dfrac{(4\cdot39) - 32}{9} \\\\\\ \dfrac{TC}{5} =\dfrac{156 - 32}{9} \\\\\\ \dfrac{TC}{5} =\dfrac{124}{9} \\\\\\ 9TC = 5\cdot124 \\\\\\ 9TC = 620 \\\\\\ TC =\dfrac{620}{9} \\\\\\ TC = 68,8 \dfrac{TC}{5} =\dfrac{TF - 32}{9} \\\\\\ \dfrac{TC}{5} =\dfrac{(4\cdot39) - 32}{9} \\\\\\ \dfrac{TC}{5} =\dfrac{156 - 32}{9} \\\\\\ \dfrac{TC}{5} =\dfrac{124}{9} \\\\\\ 9TC = 5\cdot124 \\\\\\ 9TC = 620 \\\\\\ TC =\dfrac{620}{9} \\\\\\ TC = 68,8](https://tex.z-dn.net/?f=%5Cdfrac%7BTC%7D%7B5%7D+%3D%5Cdfrac%7BTF+-+32%7D%7B9%7D+%5C%5C%5C%5C%5C%5C+%5Cdfrac%7BTC%7D%7B5%7D+%3D%5Cdfrac%7B%284%5Ccdot39%29+-+32%7D%7B9%7D+%5C%5C%5C%5C%5C%5C+%5Cdfrac%7BTC%7D%7B5%7D+%3D%5Cdfrac%7B156+-+32%7D%7B9%7D+%5C%5C%5C%5C%5C%5C+%5Cdfrac%7BTC%7D%7B5%7D+%3D%5Cdfrac%7B124%7D%7B9%7D+%5C%5C%5C%5C%5C%5C++9TC+%3D+5%5Ccdot124+%5C%5C%5C%5C%5C%5C+9TC+%3D+620+%5C%5C%5C%5C%5C%5C+TC+%3D%5Cdfrac%7B620%7D%7B9%7D+%5C%5C%5C%5C%5C%5C+TC+%3D+68%2C8)
Resposta :
68,8 °C
Resposta :
68,8 °C
Bya20011:
Na pergunta só tem isso mesmo !
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