transforma em produto y= sen a+ sen b+ sen c - sen (a+b+c)
Soluções para a tarefa
Respondido por
3
Bom dia Rillary!
Solução!
![y=sena+senb+senc-sen(a+b+c)\\\\\\
y=sen(a+b+c)-sen(a+b+c)\\\\\\\
\boxed{a+c=d}\\\\\\\
y=sen(d+b)-sen(d-b)](https://tex.z-dn.net/?f=y%3Dsena%2Bsenb%2Bsenc-sen%28a%2Bb%2Bc%29%5C%5C%5C%5C%5C%5C%0Ay%3Dsen%28a%2Bb%2Bc%29-sen%28a%2Bb%2Bc%29%5C%5C%5C%5C%5C%5C%5C%0A%5Cboxed%7Ba%2Bc%3Dd%7D%5C%5C%5C%5C%5C%5C%5C%0Ay%3Dsen%28d%2Bb%29-sen%28d-b%29%0A "y=sena+senb+senc-sen(a+b+c)\\\\\\
y=sen(a+b+c)-sen(a+b+c)\\\\\\\
\boxed{a+c=d}\\\\\\\
y=sen(d+b)-sen(d-b)")
![\boxed{Lembrando!\\\\\
Sen(a+b)~~
Sen(a-b)}~~Arco~~duplo](https://tex.z-dn.net/?f=%5Cboxed%7BLembrando%21%5C%5C%5C%5C%5C%0ASen%28a%2Bb%29%7E%7E%0ASen%28a-b%29%7D%7E%7EArco%7E%7Eduplo "\boxed{Lembrando!\\\\\
Sen(a+b)~~
Sen(a-b)}~~Arco~~duplo")
![y=sen(d).cos(b)+sen(b).cos(d)-sen(d).cos(b)+sen(b).cos(d)\\\\\\
y=2sen(b).cos(d)\\\\\\\
y=2sen(b).cos(a+c)\\\\\\\
\boxed{Resposta:~~y=2sen(b).cos(a+c)}](https://tex.z-dn.net/?f=y%3Dsen%28d%29.cos%28b%29%2Bsen%28b%29.cos%28d%29-sen%28d%29.cos%28b%29%2Bsen%28b%29.cos%28d%29%5C%5C%5C%5C%5C%5C%0Ay%3D2sen%28b%29.cos%28d%29%5C%5C%5C%5C%5C%5C%5C%0Ay%3D2sen%28b%29.cos%28a%2Bc%29%5C%5C%5C%5C%5C%5C%5C%0A%5Cboxed%7BResposta%3A%7E%7Ey%3D2sen%28b%29.cos%28a%2Bc%29%7D "y=sen(d).cos(b)+sen(b).cos(d)-sen(d).cos(b)+sen(b).cos(d)\\\\\\
y=2sen(b).cos(d)\\\\\\\
y=2sen(b).cos(a+c)\\\\\\\
\boxed{Resposta:~~y=2sen(b).cos(a+c)}")
Bom dia!
Bons estudos!
Solução!
Bom dia!
Bons estudos!
Perguntas interessantes
Matemática,
7 meses atrás
Inglês,
7 meses atrás
Português,
7 meses atrás
Matemática,
1 ano atrás
História,
1 ano atrás
Matemática,
1 ano atrás
História,
1 ano atrás