Question

Tô ferrraddooo
Se f(x)=x^3-2x^2+10, determine f(0), f(-1), f(2), f(-2) e f(A+1). obs: isso: ^ significa que está elevado

Answer 1

$f(x)=x^3-2x^2+10$

$f(0)=0^3-2\cdot0^2+10$
$f(0)=10$

$f(-1)=(-1)^3-2\cdot(-1)^2+10$
$f(-1)=-1-2+10$
$f(-1)=7$

$f(2)=2^3-2\cdot2^2+10$
$f(2)=8-2\cdot4+10$
$f(2)=8-8+10$
$f(2)=10$

$f(-2)=(-2)^3-2\cdot(-2)^2+10$
$f(-2)=-8-2\cdot4+10$
$f(-2)=-8-8+10$
$f(-2)=-6$

$f(A+1)=(A+1)^3-2\cdot(A+1)^2+10$
$f(A+1)=A^3+2A^2+A+A^2+2A+1-2\cdot(A^2+2A+1)+10$
$f(A+1)=A^3+3A^2+3A+1-2A^2+4A+2+10$
$f(A+1)=A^3+5A^2+7A+11$