Question

$y {}^{2} + 2y + 1$
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Answer 1

${y}^{2} + 2y + 1 = 0 \\ y = \frac{ - 2 + - \sqrt{ {2}^{2} - 4 \times 1 \times 1 } }{2 \times 1} \\ y = \frac{ -2 + - \sqrt{4 - 4} }{2} \\ y = \frac{ - 2 + - \sqrt{0} }{2} \\ y = - \frac{ 2}{2} \\ y = - 1$