Question

${x }^{2} - 7x + 12 = 0$
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Answer 1

Resposta:

S = {x ∈ R | x = 3 ou x = 4)

Explicação passo-a-passo:

x² - 7x + 12 = 0

Δ = b² -4ac

Δ = (-7)² -4.1.12

Δ = 49 - 48

Δ = 1

x = -b ±√Δ/2a

x' = 7 + 1 /2

x' = 4

x'' = 7 - 1 / 2

x'' = 3

Answer 2

x² - 7x + 12 = 0

A= 1

B= - 7

C= 12

∆= b² - 4ac

∆= ( - 7)² - 4 • 1 • 12

∆= 49 - 48

∆= 1

x= - b ± √∆ / 2a

x= - ( - 7) ± √1 / 2 • 1

x'= 7 + 1/2 = 8/2 = 4

x''= 7 - 1/2 = 6/2 =3

S= ( 4 , 3)