Question

$- x ^{2} + 6x + 12 = 0$
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Answer 1

- x² + 6x + 12 = 0

x² - 6x - 12 = 0

Δ = (- 6)² - 4.1.(- 12)

Δ = 36 + 48

Δ = 84

√Δ = ± 2√21

x = (6 ± 2√21)/2

x' = (6 - 2√21)/2 = 3 - √21

x'' = 3 + √21