Question

$x^{2} -3 \sqrt{2} x+4=0$

Answer 1

Δ=$b^{2}-4.a.c$
$(-3 \sqrt{2} )^{2}-4.1.4=9.2-16=18-16=2$

$x= \frac{-b+ou- \sqrt{Δ} }{2.a}$
$x= \frac{-(-3 \sqrt{2} )+ou- \sqrt{2} }{2.1}$
$x= \frac{3 \sqrt{2}+ou- \sqrt{2} }{2}$


$x= \frac{3 \sqrt{2}+ \sqrt{2} }{2}= \frac{4 \sqrt{2}}{2} =2 \sqrt{2}$

$x= \frac{3 \sqrt{2}- \sqrt{2} }{2}= \frac{2 \sqrt{2}}{2} = \sqrt{2}$

x é =$2 \sqrt{2}$ ou $\sqrt{2}$