Question

$x {}^{2} - 11x + 10 = 0$
Equação do 2°grau-Fórmula de Bháskara ​

Answer 1

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Têm-se a equação:

${\color{blue}{x^2-11x+10=0}}$

$\left\{\begin{array}{cc}a=1\\b=-11\\c=10\\\end{array}\right$

Bhaskara:

$\large\boxed{\boxed{{x_{1,2}=\frac{-b\pm\sqrt{b^2-4*a*c}}{2*a}}}}}}$

$x_{1,2}=\frac{11\pm\sqrt{(-11)^2-4*1*10}}{2*1}$

$x_{1,2}=\frac{11\pm\sqrt{121-40}}{2}$

$x_{1,2}=\frac{11\pm\sqrt{81}}{2}$

$x_{1,2}=\frac{11\pm\:9}{2}$

$x_{1}=\frac{11+9}{2}$

$x_{1}=\frac{20}{2}$

${\color{blue}{x_{1}=10}}$

$x_{2}=\frac{11-9}{2}$

$x_{2}=\frac{2}{2}$

${\color{blue}{x_{2}=1}}$

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