Question

$\sqrt{49} +\sqrt[3]{27} +\sqrt[5]{1024} =$

Answer 1

Resposta:

$12$

Explicação passo-a-passo:

$\sqrt{49}+\sqrt[3]{27}+\sqrt[5]{1024}=\\\sqrt{7\times7}+\sqrt[3]{3\times3\times3}+\sqrt[5]{2\times2\times2\times2\times2}=\\\sqrt{7^2}+\sqrt[3]{3^3}+\sqrt[5]{2^5}=\\7+3+2=\\10+2=\\12$