Question

$log_{0.2}(x + 1) \geqslant - 1$
​

Answer 1

Resposta:

log[0,2]  (x+1) >= -1

x+1>= 0,2^(-1)

x+1 >= (2/10)^(-1)

x+1 >= 10/2

x+ 1 >= 5

x >=4

Answer 2

Explicação passo-a-passo:

Inequação Logarítmica:

$\mathsf{\log_{(0,2)}(x+1)≥-1 }$

$\mathsf{\Bigg(\dfrac{2}{10}\Bigg)^{-1}~≤~x+1 }$

$\mathsf{\dfrac{10}{2}~≤~x+1 }$

$\mathsf{x+1~≥~5 }$

$\mathsf{x~≥~5-1 }$

$\mathsf{x~≥~4 }$

Espero ter ajudado bastante!)