Question

$\left \{ {{3x-2y=-1} \atop {2x+5y=12}} \right.$

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Answer 1

$\begin{cases}3x - 2y = -1 \\ 2x + 5y = 12\end{cases} \\ \\ \\ 3x - 2y = -1 \\ 3x = -1 + 2y \\ \\ \boxed{x = \dfrac{2y-1}{3}} \\ \\ \\ 2x + 5y = 12 \\ \\ 2\left(\dfrac{2y-1}{3}\right) + 5y = 12 \\ \\ \dfrac{4y-2}{3} + 5y = 12 ~~~~~~~~\times3\\ \\ 4y-2 + 15y = 36 \\ \\19y = 38 \\ \\ y = \frac{38}{19} \\ \\ \boxed{y = 2} \\ \\ 3x - 2y = 1 \\ 3x - 4 = -1 \\ \\ 3x = 3 \\ \\ \boxed{x = 1}$