Question

$\frac{x}{ x+3} = \frac{3x}{5x-1}$

Answer 1

$\frac{x}{ x+3} = \frac{3x}{5x-1} \\ \\ x(5x-1)=3x(x+3)\\ \\ 5x^2-x=3x^2+9x\\ \\ 2x^2-10x=0\\ \\ 2x(x-10)=0 \Rightarrow x=0 \ \ ou \ \ x=10$