Question

$\frac{ \times + 3}{ \times } = 1 + \frac{1 - \times }{ 2 \times }$
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Answer 1

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$\sf\dfrac{x+3}{x}=1+\dfrac{1-x}{2x}\\\underline{\tt multiplicando~os~dois~lados~por~2x~temos:}\\\sf 2x\cdot\dfrac{(x+3)}{x}=2x\cdot1+2x\cdot\dfrac{(1-x)}{2x}\\\underline{\tt simplificando~temos:}\\\sf2\diagup\!\!\!\!x\cdot\dfrac{(x+3)}{\diagup\!\!\!\!x}=2x\cdot1+\diagdown\!\!\!\!\!\!2x\cdot\dfrac{(1-x)}{\diagdown\!\!\!\!\!\!2x}\\\underline{\rm a~equac_{\!\!,}\tilde ao~equivalente~\acute e:}\\\sf 2\cdot(x+3)=2x+1-x\\\underline{\tt eliminando~os~par\hat enteses:}$

$\sf 2x+6=2x+1-x\\\sf \diagdown\!\!\!\!\!\!2x-\diagdown\!\!\!\!\!\!2x+x=1-6\\\huge\boxed{\boxed{\boxed{\boxed{\sf x=-5}}}}\blue{\checkmark}$