Question

$\frac{ \sqrt{2} }{ \sqrt{2-1} } - \frac{1}{ \sqrt{2} } - \frac{3}{ \sqrt{1+2} }$

respondam,por favor

Answer 1

$\dfrac{ \sqrt{2} }{ \sqrt{2 - 1} } - \dfrac{ \sqrt{1} }{ \sqrt{2} } - \dfrac{ 3 }{ \sqrt{1 + 2} } \\ \\ \\ \dfrac{ \sqrt{2} }{ \sqrt{1} } - \dfrac{ \sqrt{1} }{ \sqrt{2} } - \dfrac{ 3}{ \sqrt{3} } \\ \\ \\ \dfrac{ \sqrt{2} }{1 } - \dfrac{ 1 * \sqrt{2} }{ \sqrt{2} * \sqrt{2} } - \dfrac{3* \sqrt{3} }{ \sqrt{3} * \sqrt{3}} \\ \\ \\ \sqrt{2} - \dfrac{ \sqrt{2} }{ 2} } - \dfrac{3* \sqrt{3} }{ 3 } \\ \\ \\ \sqrt{2} - \dfrac{ \sqrt{2} }{ 2} } - \sqrt{3}$

$\sqrt{2} - \dfrac{ \sqrt{2} + 2 \sqrt{3} }{ 2} } \\ \\ \\ - \dfrac{-\sqrt{2} + 2 \sqrt{3}}{ 2}} \\ \\ \\=> \dfrac{\sqrt{2} - 2 \sqrt{3}}{ 2}}$