Question

$\frac { 8 } { \sqrt [ 3 ] { 2 ^ { 2 } } } =$
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Answer 1

$\cfrac{8}{\sqrt[3]{2^2} } = \cfrac{8\sqrt[3]{2^2}}{\sqrt[3]{2^2} \cdot \sqrt[3]{2^2} } = \cfrac{8\sqrt[3]{2^2}}{2^2} = \cfrac{8\sqrt[3]{4}}{4} = 2\sqrt[3]{4}$