Question

$<var>\frac{3x-2}{3} - \frac{4-x}{2} + 2 = \frac{3x-5}{6} + 2x </var>$

Answer 1

$\frac{3x-2}{3}- \frac{4-x}{2}+2= \frac{3x-5}{6}+2x$

$\frac{3x-2}{3}- \frac{4-x}{2}+ \frac{4}{2}= \frac{3x-5}{6}+ \frac{4x}{2}$

Tirando o MMC dos denominadores, obtemos 6:

$\frac{2(3x-2)-3(4-x)+3*4}{\not6}= \frac{1*(3x-5)+3*4x}{\not6}$

$6x-4-12+3x+12=3x-5+12x\\ 9x-4=15x-5\\ 9x-15x=-5+4\\ -6x=-1\\ \\ x= \frac{-1}{-6}\\\\ \boxed{x= \frac{1}{6}}$

Espero ter ajudado e tenha ótimos estudos ;)