Question

$\frac{3}{x} -4= x+ \frac{6}{2x}$

Answer 1

$\frac{3}{x}-4=x+\frac{6}{2x}\\ \\ 6-8x=2x^2+6\\ \\ 2x^2+8x=0\\ \\ 2x(x+4)=0\\ \\ x=0 \ \ \ ou x=-4\\ \\ S=\{0,-4\}$