Question

$\frac{1-x²}{xy+1}$ Quando X=0,5 e Y= -8
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Answer 1

$\dfrac{1-x^{2}}{xy+1}=\ \dfrac{1-0,5^{2}}{0,5\cdot -8+1}=\ \dfrac{1-\left(\dfrac{1}{2}\right)^{2}}{\dfrac{1}{2}\cdot -8+1}=\ \dfrac{1-\dfrac{1}{4}}{\dfrac{-8}{2}+1}=\ \dfrac{\dfrac{1\cdot 4-1}{4}}{-4+1}=\\ \\ \\ \dfrac{\dfrac{4-1}{4}}{-3}=\dfrac{\dfrac{3}{4}}{-3}=\dfrac{3}{4}\cdot -\dfrac{1}{3}=\dfrac{\not 3}{4}\cdot -\dfrac{1}{\not 3}=-\dfrac{1}{4}=-0,25$