Question

$(7 \sqrt{3}) {}^{2} = \\ ( \sqrt[3]{8}) {}^{5} = \\ (5 \sqrt{x - y} ) {}^{2} = \\ 3\frac{2}{3} =$
Espero por uma humilde resposta para esta pergunta​

Answer 1

Olá, boa noite!

Resposta:

O resultado de cada expressão apresentada no enunciado acima, será:

$\ \Large{\color{blue}{\boxed{\boxed{\boxed{\color{green}{\mathsf{(7 \sqrt{3}) {}^{2} =147 }}}}}}}$

$\ \Large{\color{blue}{\boxed{\boxed{\boxed{\color{green}{\mathsf{( \sqrt[3]{8}) {}^{5} =32}}}}}} }$

$\ \Large{\color{blue}{\boxed{\boxed{\boxed{\color{green}{\mathsf{(5 \sqrt{x - y} ) {}^{2} =25x-25y}}}}}} }$

$\ \Large{\color{blue}{\boxed{\boxed{\boxed{\color{green}{\mathsf{ 3\frac{2}{3} = \dfrac{11}{3}}}}}}}}$

Explicação passo-a-passo:

Para que possamos resolver cada expressão, devemos simplificar todos os termos possíveis de cada questão.

• Observe:

$\mathsf{(7 \sqrt{3})^2} \\ \mathsf{49\sqrt[\cancel{2}]{3^{\cancel{2}}}} \\ \mathsf{49 \cdot 3} \\ \boxed{\color{green}{\mathsf{147}}}$

==========

$\mathsf{(\sqrt[3]{8})^5 }\\ \mathsf{\sqrt[3]{2^3 }^5} \\ \mathsf{\sqrt[\cancel{3}]{2^{\cancel{3} }}^5} \\ \mathsf{2^5} \\ \boxed{\color{green}{\mathsf{32}}}$

==========

$\mathsf{(5 \sqrt{x-y})^2} \\ \mathsf{25\sqrt{x-y}^2} \\ \mathsf{25(x-y)} \\ \boxed{\color{green}{\mathsf{25x-25y}}}$

==========

$\mathsf{3 \dfrac{2}{3}} \\ \\ \mathsf{\dfrac{3 \cdot 3 + 2}{3}} \\ \\ \boxed{\color{green}{\mathsf{\dfrac{11}{3}}}}$

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Espero ter colaborado.

$\Large{\boxed{\boxed{\Leftarrow \textrm{\color{purple}{Atte:} \color{red}{ Deskroot}} \Rightarrow}}}$

Answer 2

Oie, Td Bom?!

➣ $(7 \sqrt{3} ) {}^{2} ⟹7 {}^{2} \times \sqrt{3} {}^{2} ⟹49 \times 3 = 147$

➣ $( \sqrt[3]{8} ) {}^{5} ⟹ \sqrt[3]{2 {}^{3} } {}^{5} ⟹2 {}^{5} = 32$

➣ $(5 \sqrt{x - y} ) {}^{2} ⟹5 {}^{2} \times \sqrt{x - y} {}^{2} ⟹25(x - y) = 25x - 25y$

➣ $3 \frac{3}{2} ⟹ \frac{3 \times 3 + 2}{3} ⟹ \frac{9 + 2}{3} = \frac{11}{3}$

Att. Makaveli1996