Question

$3x(x + 1) - x = 33 - (x - 3)^{2}$
delta + x1 e x2 por favor aa​

Answer 1

Resposta:

S = { -2, 3 }

Explicação passo-a-passo:

$3x.(x+1)-x = 33-(x-3)^2\\3x^2 + 3x -x =33-(x-3).(x-3)\\3x^2 + 2x = 33 -(x^2-3x-3x+9)\\3x^2+2x = 33-x^2+6x-9\\3x^2 + x^2+2x-6x -24 = 0\\4x^2 -4x-24 = 0\\x^2 -x - 6 = 0\\\\Delta = b^2-4.a.c\\Delta =(-1)^2-4.1.(-6)\\Delta = 1+24\\Delta = 25\\\\\ X = \frac{-b+-\sqrt{Delta} }{2.a} \\X =\frac{-(-1)+-\sqrt{25} }{2.1} \\X = \frac{1 +-5}{2} \\\\x^1 = 1+5/2\\x^1 = 6/2\\x^1 = 3\\\\x^2 = 1-5/2\\x^2 = -4/2\\x^2 = -2$

Dúvidas só perguntar.