Question

$256^{2x - 3} = 1$


$19^{x} = 0$

Answer 1

256^(2x-3) = 1

2^(8.(2x-3)) = 2^0

8 . (2x-3) = 0 

2x - 3 = 0

x = 3/2







19^x = 0 não existe