Question

${25}^{x} - 6 \times {5}^{x} + 5 > 0$
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Answer 1

$25 {}^{x} - 6 \times 5 {}^{x} + 5 > 0 \\ 5 {}^{2x} - 6 \times 5 {}^{x} + 5 > 0 \\ 5 {}^{2x} > 25 {}^{x} \\ 5 {}^{2x} > 5 {}^{2x} \\ x = 1$