Question

${25}^{2x} = \sqrt{5}$

Answer 1

${25}^{2x} = \sqrt{5} \\ {( {5}^{2}) }^{2x} = {5}^{ \frac{1}{2} } \\ {5}^{4x} = {5}^{ \frac{1}{2} } \\ 4x = \frac{1}{2} \\ x = \frac{1}{2} \times \frac{1}{4} \\ x = \frac{1}{8}$