Question

$2 { \times }^{2} + 4 \times - 6 = 0$
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Answer 1

resolução!

$2 {x}^{2} + 4x - 6 = 0$

∆ = 4^2 - 4 * 2 * (-6)

∆ = 16 + 48

∆ = 64

∆ =√64

∆ = 8

X ' = - 4 + 8/4

X ' = 4/4

X ' = 1

X " = - 4 - 8/4

X " = - 12/4

X " = - 3

S = { - 3 , 1 }