Question

Teorema de Pitágoras. Calcule X e Y.

Answer 1

$\dfrac{x}{8}=\dfrac{5}{3}\Rightarrow x = \dfrac{8\times 5}{3}\Rightarrow x =\dfrac{40}{3}\\x^2=8^2+y^2\\\left( \dfrac{40}{3} \right)^2=64+y^2\\\dfrac{1600}{9}-64=y^2\\9y^2=1600-576\\y^2=\dfrac{1024}{9}\\y=\pm \sqrt{\dfrac{1024}{9}}\\y=\pm \dfrac{32}{3}\; \text{Como nao existe distancia negativa usa-se o positivo}\;\dfrac{32}{3}$

O resultado é:

$X =\dfrac{40}{3}\\Y=\dfrac{32}{3}$

Espero ter sido útil