Question

tentukan persamaan garis melalui titik A (5,10) dan tegak lurus dg garis 4x- 10y=12​

Answer 1

Resposta:

Explicação passo-a-passo:

4x- 10y - 12=0​

-10y = 12 - 4x

10y = -12 + 4x

$y = \frac{-12}{10} + \frac{4x}{10}$

$m = \frac{4x}{10}$

m = $\frac{-1}{\frac{4}{10} } = \frac{-10}{4}$

y - 10 = $\frac{-10}{4} .(x-5)$

y -10 = $\frac{-10x +50}{4}$

4y - 40 = -10x +50

10x + 4y -40 - 50 = 0

+10x + 4y=90