Question

tenho até11:00 vlw$6x^{2} -x-5=0$

Answer 1

Resposta:

Explicação passo-a-passo:

$\displaystyle\\Aplicando~a~f\'{o}rmula~de~Bhaskara~para~6x^{2}-1x-5=0~~\\e~comparando~com~(a)x^{2}+(b)x+(c)=0,~temos~a=6{;}~b=-1~e~c=-5\\\\\Delta=(b)^{2}-4(a)(c)=(-1)^{2}-4(6)(-5)=1-(-120)=121\\\\x^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(-1)-\sqrt{121}}{2(6)}=\frac{1-11}{12}=\frac{-10\div2}{12\div2}=-\frac{5}{6}\\\\x^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(-1)+\sqrt{121}}{2(6)}=\frac{1+11}{12}=\frac{12}{12}=1\\\\S=\{-\frac{5}{6},~1\}$

Answer 2

6x2 - x - 5 = 0

∆ = b2 - 4ac

∆ = ( - 1 ) 2 - 4•6•(-5)

∆ = 1 + 120

∆ = 121

X1 = ( 1 + √121 ) / 12

X1 = ( 1 + 11 ) / 12

X1 = 12 / 12

X1 = 1

X2 = ( 1 - √121 ) / 12

X2 =( 1 - 11 ) / 12

X2 = - 10 / 12 ( simplificar )

X2 = - 5 / 6