Question

Solução Equação do 2° grau x2-4x+4=0

Answer 1

Resposta:

Explicação passo a passo:

$\displaystyle Aplicando~a~f\acute{o}rmula~de~Bhaskara~para~x^{2}-4x+4=0~~e~comparando~com~(a)x^{2}+(b)x+(c)=0,~determinamos~os~coeficientes:~\\a=1{;}~b=-4~e~c=4\\\\C\acute{a}lculo~do~discriminante~(\Delta):&\\&~\Delta=(b)^{2}-4(a)(c)=(-4)^{2}-4(1)(4)=16-(16)=0\\\\C\acute{a}lculo~das~raizes:&\\x^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(-4)-\sqrt{0}}{2(1)}=\frac{4-0}{2}=\frac{4}{2}=2\\\\x^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(-4)+\sqrt{0}}{2(1)}=\frac{4+0}{2}=\frac{4}{2}=2\\\\S=\{2,~2\}$