Question

solução de (2x-5).(x-2)= - (x+2).(1-x)-4

Answer 1

2x² -4x -5x +10 = - (x -x² +2 -2x) -4

2x² -x² -9x -2x + x +10 +2 +4 = 0

x² -10x +16 = 0

$\mathsf{\Delta=b^2-4ac}$

100 -64

36 = 6²

$\mathsf{x = \frac{-b \pm \sqrt{\Delta} }{2a}}$

10 ± 6/2

5 ± 3

{8 , 2}