Question

Socorroooo
1)$\frac{10a^{3} b^{3} +8ab^{2} }{2ab^{2} } =$

2)$\frac{9x^{2}y^{3} -6x^{3}y^{2} }{3x^{2} y}$

Answer 1

Resposta:

1)

$5a^{2} b +4$

2)

${3y^{2} -2xy }$

Explicação passo-a-passo:

Simplificando:

1)

$\frac{10a^{3} b^{3} +8ab^{2}}{2ab^{2} } \\ \frac{10a^{3} b +8a }{2a} \\ \frac{10a^{2} b +8 }{2} \\ 5a^{2} b +4$

2)

$\frac{9x^{2}y^{3} -6x^{3}y^{2} }{3x^{2} y} \\ \frac{9x^{2}y^{2} -6x^{3}y }{3x^{2} }\\ \frac{9y^{2} -6xy }{3 } \\ {3y^{2} -2xy }$