Question

Socorro me ajudem pfvrrrr preciso urgente pfvrrr​

Answer 1

Resposta:

a) $[\frac{1}{2}]$

Explicação passo-a-passo:

$\frac{2(x+3)}{3} + \frac{5(2x-1)}{2} + \frac{1}{6} = 5x\\\\\frac{2x+6}{3} + \frac{10x-5}{2} + \frac{1}{6} = 5x\\\\\frac{2(2x+6) + 3(10x-5)+1} {6} =5x\\\\\frac{4x+12 + 30x-15+1} {6} =5x\\\\\frac{4x + 30x+12-15+1} {6} =5x\\\\\frac{34x-2} {6} =\frac{5x}{1}$

Multiplicando "em X":

$(34x-2).(1)=(6).(5x)\\34x-2 = 30x\\34x-30x=2\\4x=2\\x=\frac{2}{4} (:\frac{2}{2} ) = \frac{1}{2}$