Question

SOCORRO AJUDAAAA AI URGENTEEE

Determine o valor de z,sendo
Z= 6.Log2 32+ 5.log7 49- 3.log6 1296

Answer 1

Oi!

$\boxed{log_b(a) <=> b^x = a}$

$log _2(32) = x$
$2^x = 32$
$2^x = 2^5$
$\boxed{x = 5}$

$log _7(49) = x$
$7^x = 49$
$7^x = 7^2$
$\boxed{x = 2}$

$log_6(1296) = x$
$6^x = 1296$
$6^x = 6^4$
$\boxed{x = 4}$

$Z = 6 \times log_2(32) + 5 \times log_7(49) - 3 \times log_6(1296)$
$Z = 6 \times 5 + 5 \times 2 - 3 \times 4$
$Z = 30 + 10 - 12$
$\boxed{Z = 28}$

Espero ter ajudado. Bons estudos!