Question

só a 29! com calculo( se tiver) e a resposta!
obrigado

Answer 1

$a) \sqrt{2} \cdot \sqrt{32} + \sqrt{49}=\sqrt{2\cdot 32} + \sqrt{49}=\sqrt{64} + \sqrt{49}=8+7=15\\ b)\sqrt{2} + \sqrt{9} - \sqrt{2} = \sqrt{9}+\sqrt{2} - \sqrt{2} =3+0=3\\ c) \frac{ \sqrt[5]{1} }{ \sqrt[3]{8}}+ \sqrt{ \frac{1}{4} } = \frac{1}{2} + \frac{1}{2} = \frac{1+1}{2}= \frac{2}{2}=1\\ d) \sqrt{7} \cdot \sqrt{ \frac{7}{4} } - \sqrt{3} \cdot \sqrt{ \frac{3}{4}} =\sqrt{ \frac{7\cdot 7}{4} } - \sqrt{ \frac{3\cdot3}{4}}=\sqrt{ \frac{49}{4} } -\sqrt{ \frac{9}{4} } = \frac{7}{2} - \frac{3}{2}=2$