Question

sistemas aplicando o método da substituição 7x-3y=12. 2x+3y=10

Answer 1

7x-3y=12

2x+3y=10

2x=10-3y

x=10-3y/2

7(10-3y/2)-3y=12

70-21y/2-3y=12

70-21y-6y=24

-27y=24-70
-27y=-46
y=46/27

x=10-3y/2

x=10-138/27/2

x=270-138/54

x=132/54

x=66/27

x=22/9