Question

simplifique os radicais
$\sqrt{245}$
$\sqrt{200}$
$\sqrt{98}$
$\sqrt[3]{250}$
$\sqrt[5]{243}$
$\sqrt[3]{ - 64}$
$\sqrt[10]{5120}$
​

Answer 1

$\sqrt{245}=\sqrt{5\times 7^{2}}=7\sqrt{5}$

$\sqrt{200}=\sqrt{2^{3}\times 5^{2}}=\sqrt{2\times 2^{2}\times 5^{2}}=2\times 5\sqrt{2}=10\sqrt{2}$

$\sqrt{98}=\sqrt{2\times 7^{2}}=7\sqrt{2}$

$\sqrt[3]{250}=\sqrt[3]{2\times 5^{3}}=5\sqrt[3]{2}$

$\sqrt[5]{243}=\sqrt[5]{3^{5}}=3$

$\sqrt[3]{-64}=\sqrt[3]{-1\times 2^{6}}=\sqrt[3]{-1}\times \sqrt[3]{2^{3}\times 2^{3}}=-1\times 2\times 2=-4$

$\sqrt[10]{5120}=\sqrt[10]{2^{10}\times 5}=2\sqrt[10]{5}$