Question

Simplifique o máximo possível os radicais a seguir​

Answer 1

Resposta:

a) $\sqrt{8} = \sqrt{2^{2}.2} = 2\sqrt{2}$

b) $\sqrt{12} = \sqrt{2^{2}.3} = 2\sqrt{3}$

c) $\sqrt{20} = \sqrt{2^{2} .5} = 2\sqrt{5}$

d) $\sqrt{96} = \sqrt{4^{2} .6} = 4\sqrt{6}$

e) $\sqrt{147} = \sqrt{7^{2} .3} = 7\sqrt{3}$

f) $\sqrt{300} = \sqrt{10^{2} . 3} = 10\sqrt{3}$

g) $\sqrt{90} = \sqrt{3^{2} .10} = 3\sqrt{10}$

h) $\sqrt{60} = \sqrt{2^{2} . 15} = 2\sqrt{15}$

i) $\sqrt{208} = \sqrt{4^{2} .13} = 4\sqrt{13}$

j) $\sqrt{396} = \sqrt{6^{2} .11} = 6\sqrt{11}$

Explicação passo-a-passo:

a) $\sqrt{8} = \sqrt{2^{2}.2} = 2\sqrt{2}$

b) $\sqrt{12} = \sqrt{2^{2}.3} = 2\sqrt{3}$

c) $\sqrt{20} = \sqrt{2^{2} .5} = 2\sqrt{5}$

d) $\sqrt{96} = \sqrt{4^{2} .6} = 4\sqrt{6}$

e) $\sqrt{147} = \sqrt{7^{2} .3} = 7\sqrt{3}$

f) $\sqrt{300} = \sqrt{10^{2} . 3} = 10\sqrt{3}$

g) $\sqrt{90} = \sqrt{3^{2} .10} = 3\sqrt{10}$

h) $\sqrt{60} = \sqrt{2^{2} . 15} = 2\sqrt{15}$

i) $\sqrt{208} = \sqrt{4^{2} .13} = 4\sqrt{13}$

j) $\sqrt{396} = \sqrt{6^{2} .11} = 6\sqrt{11}$