Question

Simplifique ( não consegui digitar tudo)

Answer 1

$\sqrt[4]{ {2}^{2} } = {2}^{ \frac{2}{4} } = {2}^{ \frac{1}{2} } = \sqrt{2}$

$\sqrt[6]{ {2}^{4} } = {2}^{ \frac{4}{6} } = {2}^{ \frac{2}{3} } = \sqrt[3]{ {2}^{2} } = \sqrt[3]{4}$

$\sqrt[9]{ {10}^{6} } = {10}^{ \frac{6}{9} } = {10}^{ \frac{2}{3} } = \sqrt[3]{ {10}^{2} } = \sqrt[3]{100}$

Answer 2

Resposta:

Explicação passo a passo:

89)

a) $\sqrt[4]{2^{2} }$ = $\sqrt{2}$

b) $\sqrt[6]{2^{4} }$ = $\sqrt[3]{2^{2} }$ = $\sqrt[3]{4}$

c) $\sqrt[9]{10^{6} }$ = $\sqrt[3]{10^{2} }$ = $\sqrt[3]{100}$

90)

a) $\sqrt[3]{3375}$ = $\sqrt[3]{3^{3} . 5^{3} }$ = 3 . 5 = 15

3375 I 3

1125 I 3

375 I 3

125 I 5

25 I 5

5 I 5

1

b) $\sqrt[4]{4096}$ = $\sqrt[4]{2^{4} . 2^{4} . 2^{4} }$ = 2 . 2 . 2 = 8

4096 I 2

2048 I 2

1024 I 2

512 I 2

256 I 2

128 I 2

64 I 2

32 I 2

16 I 2

8 I 2

4 I 2

2 I 2

1

c) -3$\sqrt{324}$ = -3 . $\sqrt{2^{2} . 3^{2} . 3^{2} }$ = -3 . 2 . 3. 3 = -6 . 9 = -54

324 I 2

162 I 2

81 I 3

27 I 3

9 I 3

3 I 3

1

d) 4$\sqrt[3]{216}$ = 4.$\sqrt[3]{2^{3} . 3^{3} }$ = 4. 2 . 3 = 12 . 3 = 36

216 I 2

108 I 2

54 I 2

27 I 3

9 I 3

3 I 3

1

Espero ter ajudado! ;)