Question

Simplifique (n+4)! /(n+2)! +(n+3)!

Answer 1

$\frac{(n+4)!}{(n+2)!+(n+3)!}=\frac{(n+4)(n+3)(n+2)!}{(n+2)!+(n+3)(n+2)!}=\frac{(n+4)(n+3)}{1+(n+3)}=\frac{(n+4)(n+3)}{n+4}=n+3$