Question

simplifique considerando 0 < b < a, ab > 2
a) $\frac{\sqrt{a^{2} - 2ab + b^{2} } }{a^{2} - 2ab + b^{2} }$

Answer 1

Resposta:

$\boxed{\mathtt{1/(a - b)}}$

Explicação passo-a-passo:

$\\ \displaystyle \mathsf{\frac{\sqrt{a^2 - 2ab + b^2}}{a^2 - 2ab + b^2} =} \\\\\\ \mathsf{\frac{\sqrt{(a - b)^2}}{(a - b)^2} =} \\\\\\ \mathsf{\frac{a - b}{(a - b)^2} =} \\\\\\ \boxed{\boxed{\mathsf{\frac{1}{a - b}}}}$