Question

simplifique completamente as seguintes expressões:

a) (2x²+x-1)/(x-1/2)

b)[(x+b)²-b²]/[(-x-2b)x]

Answer 1

Olá, Isa Brasil.

 

$<var>a) \frac{2x^2+x-1}{x-\frac12}=\frac{2x^2+2x-x-1}{x-\frac12}=\frac{2x^2-x+2x-1}{x-\frac12}=\frac{2x(x-\frac12)+2(x-\frac12)}{x-\frac12}=\\\\\\ =\frac{2x(x-\frac12)}{x-\frac12}+\frac{2(x-\frac12)}{x-\frac12}=2x+2=2(x+1)</var>$

 

 

$<var>b)\frac{(x+b)^2-b^2}{(-x-2b)x}=\frac{x^2+2bx+b^2-b^2}{-x^2-2bx}=\frac{x^2+2bx}{-(x^2+2bx)}=-1</var>$