Question

Simplifique as expressões
$\sqrt{128} + \sqrt{27} - \sqrt{32}$
$^4\sqrt{1024}$

Answer 1

128=2⁷ =2 * 2⁶
27=3³=3*3²
32=2⁵=2*2⁴
1024=2¹⁰ =2⁸ *2²

√128=√2⁷ =√(2 * 2⁶)=2³√2
√27=√3³=√(3*3²)=3√3
√32=√2⁵=√(2*2⁴)=2²√2

√128+√27-√32
=2³√2+3√3-2²√2
=8√2+3√3-4√2
=4√2+3√3

⁴√1024=⁴√2¹⁰ =⁴√(2⁸ *2²)=2²   *  ⁴√4 =4 *  ⁴√4