Question

simplifique:

a) $\sqrt{2+3}$

b) $\sqrt[3]{2.8}$

c) $\sqrt{32.x^4.y^3} \\ \sqrt{4.x^2.y^2}$

Answer 1

a) $\sqrt{2+3} = \sqrt{5}$

b) $\sqrt[3]{2*8} = \sqrt[3]{16} = \sqrt[3]{ 2^{4} } = 2\sqrt[3]{2}$

c) $\frac{ \sqrt{32* x^{4}* y^{3} } }{ \sqrt{4* x^{2}* y^{2} } }$  =
    $\sqrt{ \frac{32*x^{4}*y^{3} }{4* x^{2}*y^{2} } } = \sqrt{8*x^{2}*y }$  =
   $2x \sqrt{2y}$

Espero ter ajudado!