Question

simplifique a expressão
$\frac{2 {a}^{2} {x}^{2} }{3} \sqrt{( {a}^{2} {x}^{2}) {}^{ - 1} }$
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Answer 1

Explicação passo-a-passo:

Veja que:

$\sqrt{(a^2 x^2)^{-1}}=\sqrt{[(ax)^{-1}]^2}=(ax)^{-1}=\dfrac{1}{ax}$

Assim:

$\dfrac{2a^2 x^2}{3}\cdot\sqrt{(a^2 x^2)^{-1}}=\dfrac{2a^2 x^2}{3}\cdot\dfrac{1}{ax}$

$\dfrac{2a^2 x^2}{3}\cdot\sqrt{(a^2 x^2)^{-1}}=\dfrac{2ax}{3}$

Answer 2

Oie, Td Bom?!

$\frac{2a {}^{2}x {}^{2} }{3} \: . \: \sqrt{(a {}^{2}x {}^{2} ) {}^{ - 1} }$

$\frac{2a {}^{2}x {}^{2} }{3} \: . \: \sqrt{a {}^{2} x {}^{2} } {}^{ - 1}$

$\frac{2a {}^{2} x {}^{2} }{3} \: . \: (ax) {}^{ - 1}$

$\frac{2a {}^{2} x {}^{2} }{3} \: . \: a {}^{ - 1} x {}^{ - 1}$

$\frac{2a {}^{2}x {}^{2} a {}^{ - 1}x {}^{ - 1} }{3}$

$\frac{2a {}^{2 - 1}x {}^{2 - 1} }{3}$

$\frac{2a {}^{1} x {}^{1} }{3} = \frac{2ax}{3}$

Att. Makaveli1996