Question

Simplifique a expressão:
2ax2+x2+6ay+3y / 4a2−1

Answer 1

(2ax² + x² + 6ay + 3y)/(4a² - 1)

[x²(2a + 1) + 3y(2a + 1)]/(2a + 1)(2a - 1)

(2a + 1)(x² + 3y)/(2a + 1)(2a - 1)

= (x² + 3y)/(2a - 1)

Answer 2

Resposta:

$\frac{2ax^{2}+x^{2}+6ay+3y }{4a^{2}-1 }$

$\frac{x^{2}(2a+1)+3y(2a+1) }{4a^{2}-1 }$

$\frac{(x^{2}+3y)(2a+1) }{(2a+1)(2a-1)}$

$\frac{x^{2}+3y }{2a-1}$

bons estudos!